Nuclear Physics | NEB Physics | Numerical Problems
Image source : Physics Forums In \(_{Z}X^A\), Z is the number of protons, A is the atomic mass number (i.e., sum of number of protons and number of neutrons) and (A-Z) gives the number of neutrons. Calculate the binding energy per nucleon of 26 Fe 56 . Atomic mass of 26 Fe 56 is 55.9349 u and that of 1 H 1 is 1.00783 u. Mass of 0 n 1 = 1.00867 u and 1 u = 931 MeV. Solution: Given, mass of 26 Fe 56 , M = 55.9349 u mass of 1 H 1 i.e., mass of proton, m p = 1.00783 u mass of 0 n 1 , m n = 1.00867 u 1 u = 931 MeV binding energy per nucleon, \(\Delta E_{ben}\) = ? The relation to find the binding energy (when the mass is in atomic mass unit (u)) is, \[\Delta E_{be}=\Delta m \times 931\] Let's find \(\Delta m\) which is the mass defect, \[\begin{align*} \Delta m &=\text{theoretical mass of Fe nucleus} - \text{observed mass of Fe nucleus}\\ &=[Zm_p +(A-Z) m_n] - M\\ &=[26 \times 1.00783...