Scalars and Vectors | Vector Multiplication | Short Questions and Numerical Problem Solutions | Class 11 (Physics) | Physics in Depth
Vector Multiplication
Multiplication of a vector by a scalar
Let \(\vec{a}\) be the vector and \(\vec{k}\) be the scalar, if we multipy them the result is a vector (i.e., k\(\vec{a}\)).
Multiplication of a vector by a vector
Vector multiplication are not straightforward as scalar multiplication as they do not follow the ordinary rules of algebra. We can multiply any two vectors in two ways: a. Scalar product and b. Vector product
Scalar product / dot product
Consider any two vectors \(\vec{a}\) and \(\vec{b}\) inclined at an angle \(\theta\) with each other as in fig. Then we define the scalar product of these two vectors as,
The scalar product of two vectors \(\vec{a}\) and \(\vec{b}\) is the multiplication of magnitude of one vector with the projection of another vector. Here, the projection of \(\vec{a}\) onto \(\vec{b}\) is \(acos\theta\) and magnitude of \(\vec{b}\) is b and thus the scalar product of this vectors is,
Scalar product of unit vectors
Using the definition \(\vec{a}.\vec{b}=abcos\theta\), we can find the scalar product of unit vectors as follows:
Vector product / cross product
Consider any two vectors \(\vec{a}\) and \(\vec{b}\) inclined at an angle \(\theta\) with each other as in fig. Then we define the vector product of these two vectors as,
Using the definition, \(\vec{a} . \vec{b} = ab sin\theta \hat n\), we find the cross product of unit vectors. Vector product of unit vectors follows the cyclic order as in the fig. below. Remember the rule! When you cross product, the two unit vectors along the direction of arrow, the result will be the positive of the new vector along the circle and when you product them in reverse order, the result will be the negative of the new vector.
Geometrical significance / meaningThe magnitude of vector product geometrically signify the area of parallelogram as in figure. The vector product of two vectors i.e., \(\vec{a}\times \vec{b}\) is normal(perpendicular) to the plane containing \(\vec{a}\) and \(\vec{b}\).
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